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Post by Malban on Jan 17, 2018 7:38:05 GMT -5
Hi, I admit I am not overlay good at electronic stuff - but on the other hand I am interested. Today I looked at the Vectrex circuits again and came across following section: (from the Vectrex service manual) Basicly what you see is the DAC 1408, which translates incoming digital signals (Bit1-8) to analog "current" to Iout. The analog current gets converted to voltage by 1/2 half of the OpAmp LF 353 (and R 303). Now - my question, what voltages are generated to IN1 of the MUX (4052b). Are these voltages from -5V - +5V or 0V - 10V (or something completely different). (Also - what exactly does Capacitor C 315 do? I wouldn't expect a capacitor in a current to voltage circuit). Thx Malban
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Post by Kristof on Jan 30, 2018 12:08:21 GMT -5
Hi Malban,
The voltages of the Opamp output are approximately +2,35Volt (PortA = 0x7F) to -2,35Volt (PortA = -0x7F). I measured it on one of my Vectrex-units using a scope.
My opinion of C315 is that it serves as a kind of lowpass filter in order to filter away the glitches in the output when the 8 DAC input-lines are changing their values.
Regards,
Kristof
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Post by Malban on Jan 31, 2018 15:53:34 GMT -5
Thanks for the info.
I have no osciloscope - or multimeter for that matter (and if I did I'd probably have fried different devices by now). Never would have guessed the range you measured...
Malban
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Post by gauze on Jan 31, 2018 22:24:16 GMT -5
I was reading about opamps and this explanation of the cap might apply here (analog electronics give me a headache):
"The capacitor (if chosen to be large enough) reduces to a neglible value the phase shift in the feedback due to input capacitance of the op-amp (with R(esistor)) that could reduce the phase margin and potentially cause instability. So it eliminates a problem that is caused by using R(esistor) in the feedback rather than a short."
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Post by kokovec on Feb 3, 2018 16:18:59 GMT -5
Yep, it looks like the OpAmp is configured as a low-pass filter.
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